# Line slope calculator x+y=16

**Straight line given by points A[6; 10] and B[8; 8]**

## Calculation:

**Slope-intercept form of line:**y = -x+16

**Canonical form of the line equation:**x+y-16 = 0

**Parametric form of the line equation:**

x = t+6

y = -t+10 ; t ∈ R

**Slope:**m = -1

**Slope angle of line: φ =**-45° = -0.7854 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 16

**Distance line from the origin:**d

_{0}= 11.3137

**The length of the segment AB: |AB| =**2.8284

**Vector: AB =**(2; -2)

**Normal vector: n =**(1; 1)

**Midpoint of the segment AB: M =**[7; 9]

**Perpendicular Bisector equation:**2x-2y+4 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (8; 8) ; |OB| = 11.3137**

**Scalar product OA .OB = 128**

**Angle ∠ AOB = 14°2'10″ = 0.245 rad**